Quadratic Equation Problem 2?

Question

solve this equation using the quadratic formula: x^2 - 6x+8=0

Thank you

Answer 1

x^2 - 6x+8=0.....x=-b +/- sq. rt. of (b-4ac)/2a

x= -(-6) +/- sq. rt. of ((-6)-4(1)(8)/2(1)

x= 6 +/- sq rt. of ((-6)(-32))/2

x=6 +/- sq. rt. of (192)/2

x= 6 +/- sq. rt of 96

x= 6 +/- (2) sq. rt. of (6)

Answer 2

x^2 - 6x+8=0
I assume you mean: x² - 6x + 8 = 0

using the quadratic formula,
[ -b +/- square root (b² - 4ac) ] / 2a

let a = 1, b = -6, c = 8

= [ -(-6) +/- square root (-6² - 4(1)(8) ] / 2(1)
= [ 6 +/- square root (36-32) ] / 2
= [ 6 +/- square root 4 ] / 2
= (6 +/- 2)/2

x = (6 + 2)/2 = 4
or
x = (6 - 2)/2 = 2

Answer 3

x = [ 6 ±√(36 - 32) ] / 2
x = [ 6 ± 2 ] / 2
x = 4 , x = 2

Answer 4

x=[-b±sqrt(b^2 - 4ac)]/2a
= [6±sqrt(36-32)]/2
= (6±2)/2
= {2, 4}