A) the force is twice as weak
B) the force is 3 times as weak
C) the force is 4 times as weak
D) the force is 8 times as weak
If the distance between two objects increases by 4 times,what happens to the force of attraction between the two objects?
A)twice as weak
B)4 times as weak
C) 3 times as weak
D) eight times as weak
2007-06-21 11:05:41 · 5 answers · asked by Amy M 5 in Science & Mathematics ➔ Physics
thank you yes i did leave out 16 times...
2007-06-21 11:12:55 · update #1
force is inversely proportional to distance squared.
In the first question the answer is C and the answer to the second question is the force will become 16 times weak (not in option)
i am sure about this....i am a physics student.
2007-06-21 11:10:06 · answer #1 · answered by ishita s 2 · 2⤊ 0⤋
The square law applies..... like in EMF radiation. The loss of field strength is NOT a linear function...... If the distance is a linear progression.
Suppose the source has the value 1.
Source at zero meter =1
At 1m it is 1/2
At 2m it is 1/4
At 3m it is 1/8
At 4m it is 1/16th
At 5m it is 1/32nd of the original the field strength and so on.
It is a different thing when the distance progresses like 2, then 4, then 8, then 16, then 32 etc. Then the graph becomes log function.
2007-06-21 11:30:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
B) Four times a weak.
The formula is:
G = M1M2/r^2
If you cut r in half, G decreases by a factor of four.
2007-06-21 11:15:31 · answer #3 · answered by jsardi56 7 · 0⤊ 0⤋
C
2007-06-21 12:43:17 · answer #4 · answered by Anonymous · 0⤊ 0⤋
C
D
2007-06-21 11:11:57 · answer #5 · answered by miri 4 · 0⤊ 1⤋