2 ...... _..... 6
x .......... 4x^2
___________
3......_.....1
4x^2 ...........x
I know that looks stupid, but it was the only way that it looked like a complex fraction. basically, it's 2/x - 6/4x^2 divided by 3/4x^2 - 1/x
2007-06-21 10:15:33 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2/x - 6/4x^2 divided by 3/4x^2 - 1/x = -2
2007-06-21 11:09:48 · answer #1 · answered by Psygnosis 3 · 0⤊ 0⤋
Factor a -2 out of the top part so you get
-2*(3/4x^2 - 1/x)/(3/4x^2 - 1/x) The parts containing x cancel since they are the same on the top and bottom.
so you get -2.
2007-06-21 10:25:27 · answer #2 · answered by Anonymous · 0⤊ 1⤋
[2/x - 6/4x^2]/[3/4x^2 - 1/x]
Multiply by 4x^2/4x^2
[8x - 6]/[3 - 4x]
Factor a -2 from the numerator
-2[- 4x + 3]/[3 - 4x]
-2
2007-06-21 10:28:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
N = 2 / x - 6 / 4x²
N = (8x - 6) / 4x²
D = 3 / 4x² - 1 / x
D = (3 - 4x) / 4x²
N / D = (8x - 6) / (3 - 4x)
N / D = - 2.(3 - 4x) / (3 - 4x)
N / D = - 2
2007-06-21 23:55:08 · answer #4 · answered by Como 7 · 0⤊ 0⤋
(2/x - 6/4x^2)/[3/4x^2 - 1/x]
=[(8x-6)/4x^2]*[4x^2/(3-4x)]
=(8x-6)/(3-4x)
=-2(-4x+3)/(-4x+3) = -2
2007-06-21 10:30:52 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
the answer is 2
2007-06-21 10:25:01 · answer #6 · answered by Anonymous · 0⤊ 1⤋