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I can't seem to get these problems will someone plz help me!!!

I'm Adding and subtracting radical expressions

combine, if possible. Do not use a calculator or table square roots

1. √ 5 - √ 6 + 3 √ 5 - 2 √ 6

2.√ 7 - √ 63

3. 2√ 276 - 4 √ 3

4. 6√ 5y - √ 20y

2007-06-21 08:24:54 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

1. 4*SQRT(5)-3*SQRT(6)
2. SQRT(7)-SQRT(9*7) = SQRT(7)-SQRT(9)*-SQRT(7) =-2SQRT(7) and so on... you have to sepparate the numbers in its multiples and then apply a known square root

2007-06-21 08:32:32 · answer #1 · answered by DAG 1 · 0 0

Answers with Solutions

Qns. 1:

= 5^1/2 - 6^1/2 + 3 (5^1/2) - 6^1/2
= 4 (5^1/2) - 2 (6^1/2)
= 2 [ 2(5^1/2) - (6^12) ]

Qns. 2:

= √7 - (√7 * √9)
= √7 - (√7 * 3)
= √7 - 3 (√7)
= -2 √7

Qns. 3: (I'm not able to have a better answer. Sorry !)

= 2 √2 √2 √3 √23 - √2 √2 √2 √2 √3
= 8 √3 √23 - 4 √3 √2
= 4 √3 (2 √23 - √2)

Qns. 4:

= 6 (√5) - (√5y * √4)
= 6 (√5) - (√5y * 2)
= 6 (√5) - 2 (√5)
= 4 (√5)

Hope This Solutions Will Help In Answering Your Questions ;)

G0n9 G0n9™
Mathematician

2007-06-22 02:14:46 · answer #2 · answered by Kelvin 2 · 0 0

You can almost think of radicals as variables. For example:

2x+ 3x = 5x

Similarly

2√3 + 3√3 = 5√3

so, for #1 it can simplify to:

4√5 - 3√6

#2:

√63 can reduce to √9*√7 = 3√7

so finally you get √7 - 3√7

= -2√7

3. 2*√276 = 2*√3*√4*√23 = 4√3*√23

so, we cannot combine these because the radicals do not match up.

4. boils down to 6√5y - 2√5y

These are the same radical so we get

4√5y

2007-06-21 15:41:39 · answer #3 · answered by Anonymous · 0 0

1. Combine "like radicals"
4√5 - 3√6
The numbers in front of the square root become the coefficient.

2. Factor out perfect squares. Rewrite √63 as shown below.
√7 - √9*7
The √9 is 3 so you can pull that out and it would now be:
√7-3√7
Combine to get
-2√7

3. This is most likely factoring as well, but I dont have the time to work it out right now.

4. 6√5y - √4*5y
6√5y-2√5y
4√5y

2007-06-21 15:34:20 · answer #4 · answered by Leena P 2 · 0 0

Question 1
4√5 - 3√6

Question 2
√7 - 3√7
- 2√7

Question 3
2 x 7.√6 - 4.√3
14 √6 - 4 √3

Question 4
6√5 y - 2.√5 y
4√5 y

2007-06-24 13:28:58 · answer #5 · answered by Como 7 · 0 0

1. Just combine like terms
sqrt(5) - sqrt(6) + 3 sqrt(5) - 2 sqrt(6)
sqrt(5) + 3 sqrt(5) - 2 sqrt(6) - sqrt(6)
4 sqrt(5) - 3 sqrt(6)

2. Get like terms (e.g. 63 = 7 * 3^2) then combine
sqrt(7) - sqrt(63)
sqrt(7) - sqrt(7 * 3^2)
sqrt(7) - 3 sqrt(7)
2 sqrt(7)

3. factor 276 (2^2 * 3 * 23)
2 sqrt(276) - 4 sqrt(3)
2 sqrt( 2^2 * 3 * 23) - 4 sqrt(3)
2 * 2 sqrt(3 * 23) - 4 sqrt(3)
4 sqrt(69) - 4 sqrt(3)
4(sqrt(69) - sqrt(3))
4 sqrt(3) (sqrt(23) - 1)

4. 20 = 2^2 * 5, after taking the 2 out, you have like terms of sqrt(5y)
6 sqrt(5y) - sqrt(20y)
6 sqrt(5y) - sqrt(2^2 * 5y)
6 sqrt(5y) - 2 sqrt(5y)
4 sqrt(5y)

2007-06-21 15:40:03 · answer #6 · answered by Alex 4 · 0 0

1. 4sqrt(5) - 3sqrt(6)
2. -2sqrt(7)
3. i don't think you can add them
4. 4sqrt(5y)

2007-06-21 15:32:21 · answer #7 · answered by Adam G 2 · 0 0

? i love i guy dum
e-mail me
superstar_shay14@yahoo.com

2007-06-21 15:28:11 · answer #8 · answered by Sinead W 1 · 0 0

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