1. 4*SQRT(5)-3*SQRT(6)
2. SQRT(7)-SQRT(9*7) = SQRT(7)-SQRT(9)*-SQRT(7) =-2SQRT(7) and so on... you have to sepparate the numbers in its multiples and then apply a known square root
2007-06-21 08:32:32
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answer #1
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answered by DAG 1
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Answers with Solutions
Qns. 1:
= 5^1/2 - 6^1/2 + 3 (5^1/2) - 6^1/2
= 4 (5^1/2) - 2 (6^1/2)
= 2 [ 2(5^1/2) - (6^12) ]
Qns. 2:
= â7 - (â7 * â9)
= â7 - (â7 * 3)
= â7 - 3 (â7)
= -2 â7
Qns. 3: (I'm not able to have a better answer. Sorry !)
= 2 â2 â2 â3 â23 - â2 â2 â2 â2 â3
= 8 â3 â23 - 4 â3 â2
= 4 â3 (2 â23 - â2)
Qns. 4:
= 6 (â5) - (â5y * â4)
= 6 (â5) - (â5y * 2)
= 6 (â5) - 2 (â5)
= 4 (â5)
Hope This Solutions Will Help In Answering Your Questions ;)
G0n9 G0n9â¢
Mathematician
2007-06-22 02:14:46
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answer #2
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answered by Kelvin 2
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You can almost think of radicals as variables. For example:
2x+ 3x = 5x
Similarly
2â3 + 3â3 = 5â3
so, for #1 it can simplify to:
4â5 - 3â6
#2:
â63 can reduce to â9*â7 = 3â7
so finally you get â7 - 3â7
= -2â7
3. 2*â276 = 2*â3*â4*â23 = 4â3*â23
so, we cannot combine these because the radicals do not match up.
4. boils down to 6â5y - 2â5y
These are the same radical so we get
4â5y
2007-06-21 15:41:39
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answer #3
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answered by Anonymous
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1. Combine "like radicals"
4â5 - 3â6
The numbers in front of the square root become the coefficient.
2. Factor out perfect squares. Rewrite â63 as shown below.
â7 - â9*7
The â9 is 3 so you can pull that out and it would now be:
â7-3â7
Combine to get
-2â7
3. This is most likely factoring as well, but I dont have the time to work it out right now.
4. 6â5y - â4*5y
6â5y-2â5y
4â5y
2007-06-21 15:34:20
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answer #4
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answered by Leena P 2
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Question 1
4â5 - 3â6
Question 2
â7 - 3â7
- 2â7
Question 3
2 x 7.â6 - 4.â3
14 â6 - 4 â3
Question 4
6â5 y - 2.â5 y
4â5 y
2007-06-24 13:28:58
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answer #5
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answered by Como 7
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1. Just combine like terms
sqrt(5) - sqrt(6) + 3 sqrt(5) - 2 sqrt(6)
sqrt(5) + 3 sqrt(5) - 2 sqrt(6) - sqrt(6)
4 sqrt(5) - 3 sqrt(6)
2. Get like terms (e.g. 63 = 7 * 3^2) then combine
sqrt(7) - sqrt(63)
sqrt(7) - sqrt(7 * 3^2)
sqrt(7) - 3 sqrt(7)
2 sqrt(7)
3. factor 276 (2^2 * 3 * 23)
2 sqrt(276) - 4 sqrt(3)
2 sqrt( 2^2 * 3 * 23) - 4 sqrt(3)
2 * 2 sqrt(3 * 23) - 4 sqrt(3)
4 sqrt(69) - 4 sqrt(3)
4(sqrt(69) - sqrt(3))
4 sqrt(3) (sqrt(23) - 1)
4. 20 = 2^2 * 5, after taking the 2 out, you have like terms of sqrt(5y)
6 sqrt(5y) - sqrt(20y)
6 sqrt(5y) - sqrt(2^2 * 5y)
6 sqrt(5y) - 2 sqrt(5y)
4 sqrt(5y)
2007-06-21 15:40:03
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answer #6
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answered by Alex 4
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1. 4sqrt(5) - 3sqrt(6)
2. -2sqrt(7)
3. i don't think you can add them
4. 4sqrt(5y)
2007-06-21 15:32:21
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answer #7
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answered by Adam G 2
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? i love i guy dum
e-mail me
superstar_shay14@yahoo.com
2007-06-21 15:28:11
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answer #8
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answered by Sinead W 1
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