A. ±1,±2,±3,±6,±7,±14,±21,±42,±1/2,±3/2,±7/2,±21/2
B. ±1,±2,±6,±7,±21,±42,±1/2,±7/2,±21/2
C. ±1,±2,±3,±6,±7,±14,±21,±42,±2/3,±7/2,±21/2
D. ±1,±2,±3,±6,±7,±14,±21,±42,±1/2,±2/7,±21/2
2007-06-21 06:08:13 · 5 answers · asked by Irina L 1 in Science & Mathematics ➔ Mathematics
since you ask for "rational" roots here... I'm unable to assist.... my apologies :-))
2007-06-21 06:10:24 · answer #1 · answered by freebird31wizard 6 · 0⤊ 3⤋
x^3 => only 3 roots
divisors of -42 = ±1,±2,±3,±6,±7,±14,±21,±42
2007-06-21 13:16:49 · answer #2 · answered by harry m 6 · 1⤊ 0⤋
List all factors of the last number (constant) and call them P
+- 1,2,3,6,7,14,21,42
Next list all factors of the first coeeficient and call them Q
1,2
Then list all P/Q in simplest form without repeats
+- 1,2,3,6,7,21,42, 1/2, 3/2, 7/2, 21/2
2007-06-21 13:14:40 · answer #3 · answered by gfulton57 4 · 2⤊ 0⤋
http://www.1728.com/cubic.htm
cubic equation solver
Or plug in some offered values and see what flies. A cubic equaton only has three roots.
2007-06-21 13:17:17 · answer #4 · answered by Uncle Al 5 · 1⤊ 0⤋
Thats easy. C!
2007-06-21 13:11:09 · answer #5 · answered by vae4usc 3 · 2⤊ 0⤋