how much energy would it take to remove a single electron from the surface of the metal?
a) 7.25 X 10^ -19 J
b) 1.45 X 10^ -18 J
c) 6.90 X 10^ 17 J
d) 3.53 X 10^ -18 J
e)1.45 X 10^ -21 J
2007-06-21 05:46:54 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
1 mol of electron = 6.023 x 10^23 nos electron.
=> reqd. energy to remove a single electron = 873 x 10³ / 6.023 x 10^23 J
= 1.45 x 10^ -18 J
=> option (b) is correct.
2007-06-21 05:55:41 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 0⤋
b) 1.45 X 10^ -18 J
2007-06-21 12:55:40 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋
To get to the answer, first convert kJ into J by multiplying by 1000. Next to convert kJ/mol into kJ/electron, divide by Avogadro's number, and you'll have your answer.
2007-06-21 12:51:52 · answer #3 · answered by hcbiochem 7 · 1⤊ 0⤋
b) 1mole is 6.02x10^23 electrons - 873000J
1 electron - x
so x=873000*1/6.02x10^23 (simple proportion)
2007-06-21 12:50:35 · answer #4 · answered by Chris 5 · 1⤊ 1⤋