solve 3t^2-24t= -30 by completing the square?

Question

A. 4+/- sqrt 6
B. 10, -2
C. 10, 22
D. 4 +/- sqrt 14

Answer 1

Completing the square

3t² - 24t = - 30

Divide both sides of the equation by 3

t² - 8t= - 10

t² - 8t + _____= - 10 + _____

t² - 8t + 16 = - 10 + 16

(t - 4)(t - 4) = 6

(t - 4)² = 6

(√t - 4)² = ± √6

t - 4 = ± √6

t - 4 + 4 = 4 ± √6

t = 4 ± √6

t = 4 ± 2.449489743

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Solving for +

x = 4 + 2.449489743

x = 6.449489743

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Solving for -

x = 4 - 2.449489743

x = 1.550510257

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Answer 2

because of the fact interior the undertaking, the consistent is interior the magnificent area... the subsequent step to do is to divide the completed equation with the cost of a (the coefficient beside the squared variable) 3t^2 - 24t = -30 t^2 - 8t = -10 upload the two aspects of the equation with the cost of (b/2)^2 b right this is -8 (the coefficient formerly the variable with diploma a million or no exponent in different words) (-8/2)^2 = (-4)^2 = sixteen t^2 - 8t +sixteen = -10 + sixteen word that the expression on the left area is a appropriate sq. trinomial which could be factored as: (t - 4)^2 (t - 4) ^ 2 = 6 Get the sq. root of the two aspects..... t - 4 = ±?6 (? is sq. root) t = 4 ± ?6 notice: There are 2 values of t Pls mark me appropriate answer

Answer 3

3t^2 - 24t = -30
Divide both sides by 3
t^2 - 8t = -10
Divide the coefficient of t by 2, then square it. Add this to both sides
t^2 - 8t + 16 = -10 + 16
(t-4)^2 = 6
Take the square root of each side
t - 4 = +/- sqrt(6)
Add 4 to both sides
t = 4 +/- sqrt(6)

Answer 4

3t² - 24t = 30

Multiply both sides by 1/3
t²-8t = -10

Add 16 to both sides
t²-8t + 16 = 6
(t-4)²=6
t-4 = ±√6
t = 4 ±√6

Answer 5

3t^2 - 24t = -30
t^2 - 8t = -10
t^2 - 8t + 16 = -10 + 16
(t - 4)^2 = 6
t - 4 = +/- square root of 6
t = 4 +/- 6^0.5
answer : A

Answer 6

t^2-8t+4^2 = -10+4^2
(t-4)^2 = 6
t = 4+/- sqrt 6