what is the period of this funtion?
y=2sin2x+tgx
2007-06-21 04:40:53 · 2 answers · asked by murzilka 1 in Science & Mathematics ➔ Mathematics
sin x has a period of 2π, so sin 2x, which "gets there twice as fast," has a period of π.
or did you mean sin(2x + tgx)? then you have sin[(2+tg)x], which has a period of 2π/(2+tg).
2007-06-21 04:51:23 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
The period of the given function is pi.
You should know that period of sinx is 2*pi. So sin2x is in fact twice as fast as sinx. That is why the period of 2sin2x (the first part of the given expression) is (2*pi)/2=pi.
Then you have tgx - its period is also pi. So thereis no doubt the sum of 2 functions with the period pi will also have the same period.
In general when you have two functions f1 and f2 with periods t1 and t2. A new function f=f1+f2 will have a period t, which will be the least common multiple of t1 and t2.
2007-06-21 05:04:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋