RE-arrange the formula to make G the new subject...?

Question

B = t²- g ∕ t + g

Rearrange the formula to make 'g' the new subject

Answer 1

I'm assuming there are parentheses.
B = (t^2 - g) / (t+g)
Multiply both sides by t+g
B(t+g) = t^2 - g
Distribute the B
Bt + Bg = t^2 - g
Add g to both sides and subtract Bt from both sides
Bg + g = t^2 - Bt
Factor out g
g(B+1) = t^2 - Bt
Divide both sides by (B+1)
g = (t^2 -Bt) / (B+1)

Answer 2

B = (t²- g) ∕ (t + g)

Multiply both sides by (t + g)
Bt + Bg = t² - g

Add g to each side, subtract Bt from each side
Bg + g = t² - Bt

Factor out the g on the left hand side, and the t on the right
g(B + 1) = t (t-B)

Divide each side by (B + 1) to isolate g on the left
g = t(t-B) / (B + 1)

Answer 3

4d(g + 3) = 3g + 5 Open brackets 4dg + 12d = 3g + 5 Transpose 4dg - 3g = 5 - 12d g(4d -3) = 5 - 12d Divide the two aspects with the help of (4d-3) g = (5 - 12d)/(4d-3) bear in techniques. if u upload/subtract/multiply/divide the two aspects of an equation with the help of the comparable cost, then the equation is unchanged. attempt it step with the help of step. artwork out the 2nd on your very own. additionally bear in techniques the precedence order (pedmas)

Answer 4

B = t^2-g/t+g
B(t+g)= t^2 -g
Bt +bg=T^2 -g
Bt -t^2 = -g -Bg
t(b-t) = -g(1+b)
t(b-t)/(1+b)= -g(1+b)/(1+b)
t(b-t)/(1+b)= -g
t(b-t)/(1+b)/-1 =-g/-1
t(b-t) x 1/ (1+b)/-1= g

Answer 5

B - t² = g - g/t
Bt - t^3 = gt - g
Bt - t^3 = g(t - 1)

Bt - t^3
---------- = g
.. t - 1

Answer 6

g = (t^2 - Bt)/(B + 1)