how do you evaluate 3^-4 / 4^-3
2007-06-21 04:13:41 · 9 answers · asked by What's up people!! 1 in Science & Mathematics ➔ Mathematics
Just reverse it, so it becomes...
4^3 / 3^4
which is
64/81
2007-06-21 04:16:35 · answer #1 · answered by oriolesfan2323 4 · 0⤊ 0⤋
Flip the numbers to get rid of the negative exponent so you get:
1/3^4 divided by 1/4^3
1/3*1/3*1/3*1/3 divided by 1/4*1/4*1/4
1/81 divided by 1/64
1/81 times 64/1 equals 64/81
2007-06-21 11:17:50 · answer #2 · answered by JasRitt 2 · 0⤊ 0⤋
4^3 / 3^4
= 64 / 81
2007-06-21 11:16:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3^-4 / 4^-3= 4^3/3^4 =64/81
2007-06-21 11:20:33 · answer #4 · answered by pioneers 5 · 0⤊ 0⤋
3^-4 would be rewritten as 1/(3^4). 1/(4^-3) would be rewritten as 4^3 so your equation would basically be flipped. So you have (4^3)/(3^4) = 64/81.
2007-06-21 11:19:27 · answer #5 · answered by pre.lives07 2 · 0⤊ 0⤋
3^-4 / 4^-3 = (1 / 3^4) / (1 / 4^3) = (1 / 81) / (1 / 64) = 64 / 81 = 0.79 (approximately)
2007-06-21 11:23:55 · answer #6 · answered by oregfiu 7 · 0⤊ 0⤋
64/81
2007-06-21 11:17:01 · answer #7 · answered by MathGuy 6 · 0⤊ 0⤋
64/81
3^-4=1/81
4^-3=1/64
so,3^-4 / 4^-3=64/81
2007-06-21 11:17:21 · answer #8 · answered by may_5 2 · 0⤊ 0⤋
idk dude
2007-06-21 11:21:06 · answer #9 · answered by JESSE M 1 · 0⤊ 0⤋