How do you work this out?

Question

how do you evaluate: 3+5(9-6)^2 /3-2

Answer 1

3 + 5(3)^2 / 3 - 2
3 + (5*9)/3 - 2
3 + 5 *3 -2
3 + 15 - 2
16

Answer 2

since there is no paranthesses between 3 and 2, you can not do the problem like this:

numerator:
3 + 5 * (9 - 6)^2
3 + 5 * 3^2 =
3 + 5 * 9 =
3 + 45 =
48

denominator:
3 - 2 = 1

48/1 = 48

but, you have to do it like this:
3 + [{5(9-6)^2}/3] - 2 =
3 + [{5(3^2)}/3] - 2 =
3 + [{5(9)}/3] - 2 =
3 + [{45}/3] - 2 =
3 + 15 - 2 =
16
so, the answer is 16

Answer 3

Assume question is :-
3 + (5 x 3²) / 3 - 2
= 3 + 45/3 - 2
= 3 + 15 - 2
= 16

Answer 4

Always remember: Please Excuse My Dear Aunt Sally.
Parenthesis, Exponent, Multiply & Divide (if you have both then you work from right to left), Add & Subtract (if you have both then you work from right to left). SO:

3+5(9-6)^2/3-2 Do your parenthesis!
3+5(3)^2/3-2 Do the exponent
3+5(9)/3-2 Multiply and Divide (there is both so we must work from left to right)
3+45/3-2
3+15-2 Add and subtract (there is both so we must work from left to right)
18-2
16

Answer 5

Order of operations: PEMDAS
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
I remember it by: Please Excuse My Dear Aunt Sally

So, parenthesis first:
3 + 5(3)^2 / 3 - 2

Then exponents:
3 + 5(9) / 3 - 2

Then multiplication and division, left to right:
3 + 45/3 - 2
3 + 15 - 2

Then addition and subtraction:
18 - 2
16 is your answer!