2007-06-17 02:11:47 · 7 answers · asked by appianway 1 in Science & Mathematics ➔ Engineering
For DC application: 2.0 kVA = 2.0 kW or 2000 watts.
For AC equipment, it depends on the power factor (PF)
kVA x PF = kW.
kW x 1000 = watts.
Resistance type loads have a power factor near 1.00,
so 2.0 kVA = 2.0 kW or 2000 watts.
Motors may have a power factor closer to 0.85.
In that case 2.0 kVA x 0.85 = 1.7 kW or 1700 watts.
I've seen equipment with power factors as low as 0.48.
In those applications, 2.0 kVA x 0.48 = 0.96 kW or 960 watts.
Please update your question with a description of the equipment and I'll provide an estimated power factor.
2007-06-17 02:43:13 · answer #1 · answered by Thomas C 6 · 4⤊ 0⤋
Kva To Watts
2016-11-05 03:27:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This Site Might Help You.
RE:
How many Watts does 2.0 kVA correspond to?
2015-08-16 18:00:46 · answer #3 · answered by Nida 1 · 0⤊ 0⤋
The k means thousand so 2k=2000. The V means Volts (voltage) and the A means Amps (current). So VA means VoltAmps which roughly equals Watts (without taking in to account transient effects in the circuit). So 2kVA = 2000 Watts (or about 33 60-Watt light bulbs)!
2016-03-15 02:58:20 · answer #4 · answered by ? 4 · 0⤊ 0⤋
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Actually speaking VoltageX Current = kVA Power actually comprises of kW, kVA & kVAr If the Power factor is unity then kW= kVA But normally we take an average PF of 0.8. So for your Generator Watts = kVA X 1000/0.8 ie. 2 X1000X0.8 = 1600 Watts In case you want your Generator's Kilo Watts= kVAX0.8 1.6kW Also make sure that your generator is loaded between 70 - 80% of its full load as your generator works at maximum efficiency in this range. Pls avoid loading it more than 85% of full load.
2016-04-10 03:13:12 · answer #5 · answered by ? 4 · 0⤊ 0⤋
Thomas C is right!
VA is called Real Power. There are also Watt (Resistive power) and VAR (Reactive Power).
[correct me if I wrong]
2007-06-17 18:51:00 · answer #6 · answered by amrobyono 3 · 0⤊ 0⤋
2.0kVA=2.0kWatts=2000watts
2007-06-17 02:43:17 · answer #7 · answered by Anonymous · 0⤊ 1⤋