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Find the fluid force on a plate in the shape of an isosceles trapezoid, length 5ft at the top and 9ft at the botto and height of 3ft, situated vertically in a vat of oil with weight density 60ib/ft^3. The top is 2ft below the surface of the oil. Thanks....

2007-06-13 19:57:51 · 4 answers · asked by PETL 1 in Science & Mathematics Mathematics

The plate is vertically placed in the oil.

2007-06-13 21:02:12 · update #1

4 answers

The easiest way to solve this problem is to use Archimedes' principle which states that the buoyant force on a body is equal to the total weight of the fluid it displaces.

First find the total volume occupied by the plate. I'm not sure the exact shape of the plate you're describing, but I'm sure it's clear to you.
Next, find out how much weight the same volume of fluid would have. For example, if you ended up with 5 ft^3 as the volume of the plate, the total weight of displaced fluid is:
(60 lb/ft^3) * (5 ft^3) = 300 lbs

Therefore, 300 lbs is the (upward) force on the plate. This does not depend on the material of the plate. The material of the plate does, however, determine its mass. If the plate weighs more than 300 lbs, then gravity wins over buoyancy, and the plate sinks. If the plate weighs less than 300 lbs, buoyancy wins, and the plate floats. If it weighs exactly 300 lbs, it sits there and doesn't move, since the forces on it are exactly balanced.

2007-06-13 20:26:51 · answer #1 · answered by lithiumdeuteride 7 · 0 0

Make an additional detail about the required force
Is the required force a vertical force or horizontal force?
Is the plate vertical or horizontal?

2007-06-14 03:12:13 · answer #2 · answered by CPUcate 6 · 0 0

More information is required here. Like how it is placed i.e.
horizontally,vertically,inclined.

2007-06-14 03:19:15 · answer #3 · answered by NIRAJ 2 · 0 0

the fluid force is equal to 20pounds

2007-06-14 03:06:03 · answer #4 · answered by chums12000 2 · 0 0

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