2007-06-13 18:12:43 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You can cross multiply which means multiply the denominator of one fraction by the numerator of the other and set the two products equal to one another.
3(x-1)=2(x+3)
3x-3=2x+6
x-3=6
x=9
2007-06-13 18:18:39 · answer #1 · answered by Linduh. 3 · 1⤊ 0⤋
Multiply by 6 to get rid of the fractions.
3(x-1)=2(x+3)
3x-3=2x+6
x=9
2007-06-14 01:19:56 · answer #2 · answered by gordonmorrison 6 · 0⤊ 0⤋
Firstly, use the cross multiplication method
followed by expanding the brackets
and finally bring the same term on each side :
(x-1) / (2) = (x+3) / (3)
(3)(x-1) = (2)(x+3)
3x -3 = 2x+6
3x-2x = 6+3
x=9
That's how you solve this question.
2007-06-14 01:22:36 · answer #3 · answered by DanseTanz 1 · 0⤊ 0⤋
X by 6:-
3x - 3 = 2x + 6
x = 9
2007-06-14 08:23:13 · answer #4 · answered by Como 7 · 0⤊ 0⤋
dear this is very easy . you should first multiple x-1 with 3 and 2 with x+3 and then you will have a linear question and it is easily will be x=9 ! you see ?
2007-06-14 08:13:40 · answer #5 · answered by arash 3 · 0⤊ 0⤋
2(x+3)=3(x-1)
2x+6=3x-3
9=x
2007-06-14 03:27:18 · answer #6 · answered by Irwan 2 · 0⤊ 0⤋
multiply both sides by 6.
3x -3 = 2x + 6
x = 9
2007-06-14 01:17:39 · answer #7 · answered by Alan V 3 · 2⤊ 0⤋