I have to find the area of an acute triangle.. how do I find thie height?

Question

I only have the length of the sides, how can I find the area with just this information??

Answer 1

Area of a triangle

A = 1/2 * h * b
so solve for h

[A/((1/2)*b)] = h

if i'm wrong you can always try this:
http://www.mathgoodies.com/lessons/vol1/area_triangle.html

oops should have read the rest, sorry, the ones above me got it covered.

Answer 2

Let a,b and c are the lengths of the sides of the triangle
Find half perimeter
s=(a+b+c)/2
Area of the triangle
=sqrt{s(s-a)(s-b)(s-c)} sq units
I am giving an example.Let the sides of a triangle be 6,10 and 12 cm
s=(6+10+12)/2
=28/2=14cm
Therefore area
=sqrt{14(14-6)(14-10)(14-12)}
=sqrt(14*8*4*2)
=sqrt(896)
=29.93 sq.cm

Answer 3

You could break it up into right triangles and find the length of the height using sine.

Answer 4

There are a couple of formulas to find area of triangle.

1/2 *a*b*sin C

If you have one of the angle, between any 2 lines, (i.e. a & b), then use the above formula.

Answer 5

Heron's area formula:

for a triangle with sides a, b and c:
Area = SQRT(s(s-a)(s-b)(s-c))
where: s = half perimeter
= (a+b+c)/2

Answer 6

base x height/2 =area of triangle
can be done by drawing to scale or by sine tan or cosine. hope this helps