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For each of the following, check for discontinuities and state the equation of any vertical asymptotes. Conduct a limit test to determine the asymptote from above or below.

a) y = x / x + 5

b) f(x) = 2x / x2 - 1

c) g(t) = 3t2 + 4 / t2 - 1

d)y = 3x2 - 8x - 7 / x - 4

Please show your work this would be appreciated.

2007-06-13 15:49:05 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

a) vertical asymptote at x = -5. for x > -5, graph approaches horizontal asymptote y = 1 from below, since x+5 > x, and for x < -5, graph approaches y=1 from above. 5/(5+5) = 1/2 < 1. -10/(-10+5) = 2 > 1.

b) vertical asymptotes when x² = 1, x = ±1. since lim (x→∞) 2x/x² = 0, horizontal asymptote is y = 0 for x > 1 and x < -1.

not clear what you mean by determining the asymptote from above or below.

c) vertical asymptotes at t = ±1. horizontal asymptote at lim (t→∞) 3t²/t² = 3

d) vertical asymptote at x = 4. dividing 3x² - 8x - 7 by x - 4 gives 3x + 4 as the slant asymptote. remainder 9/(x-4) → 0 as x→∞.

2007-06-13 16:10:16 · answer #1 · answered by Philo 7 · 0 0

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