_2_______ +____2____
x^2-5x+4 x^2-6x+5
____2_____ + _2________
x^2-9x+20 x^2+2x-35
2007-06-13 13:58:25 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Fractions simplify?
_2_______ +____2____
x^2-5x+4 x^2-6x+5
2/(x^2-5x+4) + 2/(x^2-6x+5) =
2/(x-1)(x-4) + 2/(x-1)(x-5) =
2(x-5)/(x-1)(x-4)(x-5) + 2(x-4)/(x-1)(x-4)(x-5) =
(2(x-5) +2(x-4)) / (x-1)(x-4)(x-5) =
(2x-10 +2x -8) / (x-1)(x-4)(x-5) =
(4x - 18) / (x-1)(x-4)(x-5)
Won't simplify further since 4x-18 = 2(2x-9)
____2_____ + _2________
x^2-9x+20x^2+2x-35
2/(x^2-9x+20) + 2/(x^2+2x-35) =
2/(x-4)(x-5) + 2 / (x+7)(x-5) =
(2(x+7) + 2(x-4)) / (x+7)(x-5)(x-4) =
(2x + 14 + 2x - 8) / (x+7)(x-5)(x-4) =
(4x -6) / (x+7)(x-5)(x-4)
Won't simplify further since 4x-6 factors to 2(2x-3)
2007-06-13 14:08:40 · answer #1 · answered by Steve A 7 · 0⤊ 0⤋
(2 / x^2-5x+4) + (2 / x^2-6x+5)
[ 2 / (x-4)(x-1) ] + [ 2 / (x-5)(x-1) ]
multiply left by (x-5) and right by (x-4)
[ 2*(x-5) + 2*(x-4) ] / [ (x-4)(x-5)(x-1) ]
2x-10+2x-8 / [ (x-4)(x-5)(x-1) ]
4x - 18 / [ (x-4)(x-5)(x-1) ] or 2(2x - 9) / [ (x-4)(x-5)(x-1) ]
(2 / x^2-9x+20) + (2 / x^2+2x-35)
[ 2 / (x-4)(x-5) ] + [ 2 / (x-5)(x+7) ]
multiply left by (x+7) and right by (x-4)
[ 2*(x+7) + 2*(x-4) ] / [ (x-4)(x-5)(x+7) ]
2x+14+2x-8 / [ (x-4)(x-5)(x+7) ]
4x + 6 / [ (x-4)(x-5)(x+7) ] or 2(2x+3) / [ (x-4)(x-5)(x+7) ]
2007-06-13 21:13:55 · answer #2 · answered by bourqueno77 4 · 0⤊ 0⤋
Could you clarify on what you are asking?
2007-06-13 21:04:52 · answer #3 · answered by krahjerdi 2 · 0⤊ 0⤋
you need to put spaces so we can read your damn problem
2007-06-13 21:05:50 · answer #4 · answered by Adeel 4 · 0⤊ 0⤋
wat level is this?
2007-06-13 21:03:17 · answer #5 · answered by Pitbull Lover 2 · 0⤊ 0⤋