I have my math B regents tomorrow and my friend and I can't figure out how to do this one problem. It's problem #20 on the NYS June 2005 regents exam (you need to scroll down and find the exam. The link from the exam doesn't work). http://www.nysedregents.org/testing/mathre/regentmathb.html
From there, you have to scroll down to the 6th page and its question #20.
Could you please include a detailed explaination? Thanks!
2007-06-13 10:58:53 · 5 answers · asked by orlandoluvr_1990 3 in Education & Reference ➔ Homework Help
http://schools.nycenet.edu/d75/HIS/shack/mathematics.html
has step by step answers to that question
2007-06-13 15:37:26 · answer #1 · answered by Mango T 2 · 0⤊ 0⤋
3
2007-06-13 18:16:55 · answer #2 · answered by ya_go_dog 2 · 0⤊ 0⤋
Remember that
sine = opposite/hypotenuse
From looking at the coordinates on the picture
we can determine that the circle is a unit circle.
All radii in the circle are equal to one.
Using that segment QO is a hypotenuse that has length one
Segment QS/ QO = QS
Segment PR can't work because it corresponds to hypotenuse PO which is greater than one
So PR couldn't be sin(theta) on it's lonesome
The answer is segment QS(4)
2007-06-13 18:16:57 · answer #3 · answered by ≈ nohglf 7 · 1⤊ 1⤋
I'm going to substitute angle a for theta...
sin a = sin (180-a)
sin a = PR/RO
RO = 1
sin a = PR
Answer 3 is correct.
2007-06-13 18:30:06 · answer #4 · answered by Automation Wizard 6 · 0⤊ 0⤋
The answer is 3 (PR)
2007-06-13 18:13:55 · answer #5 · answered by anonymous 4 · 0⤊ 0⤋