2007-06-13 10:44:13 · 5 answers · asked by John K 1 in Science & Mathematics ➔ Physics
200 lbs/14.7 psi nominal = 14 in^2
2007-06-13 10:47:32 · answer #1 · answered by Uncle Al 5 · 0⤊ 0⤋
It depends on the air pressure and on how deep the vacuum is.
If the pressure differential is 10 PSI, 20 square inches would be required.
You cannot, in a practical sense, achieve a perfect vacuum.
Air pressure varies also, depending on several factors.
Barometric pressure is a Gage of ambient air pressure, but your best indicator would be to connect a vacuum Gage to the lifting device to measure the exact pressure differential available under existing conditions. When that factor is known, you can easily calculate the area required. Multiply the difference by the square inch area of the lifting device.
If your vacuum Gage is calibrated in inches of mercury, 2.036 in. Hg. = 1 PSI.
2007-06-13 11:17:04 · answer #2 · answered by Philip H 7 · 0⤊ 0⤋
well normal atmospheric pressure is about 14.7 pounds per square inch. so to lift 200 lbs you need 200/14.7 = 13.6 square inches
2007-06-13 10:50:24 · answer #3 · answered by billgoats79 5 · 0⤊ 0⤋
I agree, the minimum is about 14 sq. inches, but if you are really going to "try this at home", I would add a safety factor of at least double that: 27 sq. inches.
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2007-06-13 10:52:49 · answer #4 · answered by tlbs101 7 · 0⤊ 0⤋
13.6 square inches.
2007-06-16 05:30:06 · answer #5 · answered by johnandeileen2000 7 · 0⤊ 0⤋