Differentiate with respect to x: 4sin²x?

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2007-06-13 10:05:01 · 5 answers · asked by attilioi t 1 in Science & Mathematics ➔ Mathematics

ok... simple chain rule... For y = 4sin²x,

dy/dx = 4*2*sin(x)*cos(x) = 8sinx*cosx

Enjoy.

2007-06-13 10:07:55 · answer #1 · answered by C-Wryte 3 · 0⤊ 2⤋

Dx( 4sin^2 (x))
take out the 4
4[ 2sin^1(x) times Dx(sin x) time Dx(x)
4[2sin(x) times cosx times 1

8sin(x)cos(x)
^^ thats your answer

2007-06-13 10:11:23 · answer #2 · answered by Lizzy G 2 · 0⤊ 0⤋

f(x) = 4sinÂ²x,
df/dx = 8*sinx*cosx

2007-06-13 10:11:32 · answer #3 · answered by fernando_007 6 · 0⤊ 0⤋

f (x) = 4.(sin x)Â²
f `(x) = (8.sin x).cos x
f `(x) = 4.(2 sinx.cos x)
f `(x) = 4.sin 2x

2007-06-13 20:23:51 · answer #4 · answered by Como 7 · 0⤊ 0⤋

8sinxcosx

2007-06-13 10:13:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋