2007-06-13 09:35:01 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
r = x/201 = 1809/x
cross multiply
x^2 = 1809 * 201
x^2 = 363609
x = sqrt(363609)
x = 603
2007-06-21 08:53:04 · answer #1 · answered by topsyk 3 · 0⤊ 0⤋
x/201=1809/x <=> x^2=201*1809 <=> x^2=363609 <=> x=603
2007-06-13 16:40:10 · answer #2 · answered by ♥*´`*•.katie.•*´`*♥ 2 · 0⤊ 1⤋
I really like kaith_29's approach! -- 'Very elegant. However, the answer is incomplete.
Here's a more primative way to look at the problem.
To get from 201 to 1809, you're going to have to multiply 201 by the common multiplier 2 times...   (once to get to x and again to get from x to 1809)
201*R^2 = 1809
R^2 = 9
R = +/- 3
So, x = 603 OR -603
Try it, -603 really does work with -3 as the common multiplier.
2007-06-13 16:52:40 · answer #3 · answered by kickthecan61 5 · 0⤊ 1⤋
x^2 = 201*1809
x = sqrt(201*1809) = 603
2007-06-13 16:42:15 · answer #4 · answered by ironduke8159 7 · 1⤊ 0⤋
201 / x = x / 1809
x^2 = (201)(1809)
x= 603 or -603
So, the sequence is
201, 603, 1809 or 201, -603, 1809
2007-06-13 16:42:53 · answer #5 · answered by mathjoe 3 · 0⤊ 1⤋
sqrt(201*1809)
2007-06-21 05:14:25 · answer #6 · answered by ps 3 · 0⤊ 0⤋