2007-06-13 06:55:58 · 4 answers · asked by Amanda H 2 in Science & Mathematics ➔ Mathematics
(x + 3)(x^2 + 3x + 1) = [ x (x^2 + 3x + 1) ] + [ 3 (x^2 + 3x + 1) ]
So multiply each term in the first bracket by each term in the second bracket.
x^3 + 3x^2 + x + 3x^2 + 9x + 3
Simplify it further by collecting like terms
x^3 + 6x^2 + 10x + 3
2007-06-13 07:35:37 · answer #1 · answered by MO 2 · 0⤊ 0⤋
= x (x^2 + 3x + 1) + 3 (x^2 + 3x + 1)
= (x^3 + 3x^2 + x) + (3x^2 + 9x + 3)
= x^3 + 6x^2 + 10x + 3
2007-06-13 07:01:55 · answer #2 · answered by buoisang 4 · 0⤊ 0⤋
= x³ + 3x² + x + 3x² + 9x + 3
= x³ + 6x² + 10x + 3
2007-06-13 07:22:55 · answer #3 · answered by Como 7 · 0⤊ 0⤋
simple version of the distributive rule is how you learned to multiply in 4th grade. when you multiply 23 x 45, it's each part of 23 times each part of 45, 4 multiplications in all (plus carries, plus carefully locating each result according to its place value).
here it's each term of (x+3) times each term of (x² + 3x + 1), 6 multiplications in all, and then add like terms. so
(x + 3)(x² + 3x + 1) =
x^3 + 3x² + x + 3x² + 9x + 3 =
x^3 + 6x² + 10x + 3
2007-06-13 07:03:45 · answer #4 · answered by Philo 7 · 0⤊ 0⤋