please help
2007-06-13 04:25:26 · 6 answers · asked by ti-ti b 1 in Science & Mathematics ➔ Mathematics
[1 ±√(1-48)] /8
1/8 [1 ± i√(47)], where i = √-1
There are no real number roots to this equation.
2007-06-13 04:30:49 · answer #1 · answered by MamaMia © 7 · 1⤊ 0⤋
The quadratic formula is -b +or- the square root of (b^2-4ac) / 2a
In your equation a=4 b=-1 and c=3
1 plus-or-minus the square root of (-1 squared -4*4*3) / 2*4
1 plus or minus the square root of (1-48) /8
1 plus or minus the square root of (-47) / 8
2007-06-13 04:38:46 · answer #2 · answered by littlemzliss 1 · 0⤊ 0⤋
yes.. quadratic formula
-(-1) +/- Sqrt [(-1^2)-4(4)(3)]/2(4)
simplifies to be 1+/- Sqrt (-47)/8
since the square root is negative, the roots are imaginary
1+ i Sqrt 47/8 and 1 - i Sqrt 47 /8
Note, entire top is divided by 8, not just the square root
2007-06-13 04:32:58 · answer #3 · answered by Tim M 1 · 0⤊ 0⤋
a = 4, b = -1, c = 3
Sub into the quadratic formula: x = [-b屉(b^2 -4ac)]/2a
x = [1屉(1-48)]/8
x = [1屉(47)]/8
Therefore, x = [1+â(47)]/8, and x = [1-â(47)]/8
2007-06-13 04:47:10 · answer #4 · answered by Eleckid 2 · 0⤊ 0⤋
sorry for being rude, but quatratic formula is pretty straight-forward. do your homework
2007-06-13 04:38:51 · answer #5 · answered by Amanda 2 · 0⤊ 0⤋
x = [1 ± â(- 47)] / 8
x = [1 ± â (47) i ] / 8
2007-06-13 04:47:30 · answer #6 · answered by Como 7 · 0⤊ 0⤋