a]8,-1/2
b]-8,4
c]-8,1
d]1,-1/2
2007-06-13 04:23:35 · 6 answers · asked by ti-ti b 1 in Science & Mathematics ➔ Mathematics
4x^2 + 28x -32 = 0
4(x^2 + 7x - 8) = 0
4(x - 1)(x + 8) = 0
x = 1, -8
2007-06-13 04:28:28 · answer #1 · answered by hawkeye3772 4 · 0⤊ 0⤋
4x^2+28x-32=0
divide thru by 4
x² + 7x - 8 = 0
(x + 8)(x - 1) = 0
x = 1, x = -8
.
2007-06-13 11:29:31 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋
ok...
4x^2 + 28x - 32 = 0
4(x^2 + 7 - 8) = 0
x^2 + 7 - 8 = 0
(x + 8)(x -1) = 0
x = -8, x = 1.
So, your answer is C.
2007-06-13 11:26:18 · answer #3 · answered by C-Wryte 3 · 0⤊ 1⤋
4(x^2+7x-8)=0
4(x-1)(x+8)=0
x=1, -8
2007-06-13 11:29:55 · answer #4 · answered by Liz 4 · 0⤊ 0⤋
x² + 7x - 8 = 0
(x + 8).(x - 1) = 0
x = - 8, x = 1
OPTION c)
2007-06-13 11:51:21 · answer #5 · answered by Como 7 · 0⤊ 0⤋
If this is an SAT question, simply plug in the numbers, and if your answers are 0, then they are roots of that polynomial.
2007-06-13 11:46:08 · answer #6 · answered by Tim M 1 · 0⤊ 0⤋