a rectangle is 4cm longer than its wide.if the lenght and width are both decreased by 24cmSquared?

Question

a rectangle is 4cm longer than its wide.if the lenght and width are both decreased by 24cmSquared.Whats the dimensions of the original rectangle?

a rectangle is 4cm longer than its wide.if the lenght and width are both decreased by 2cmSquared, the are is decreased by 24cmSquared.find the dimensions of the original rectangle?

Answer 1

Original Rectangle:
width = W
length = W + 4
Original Area = Wx(W+4)

New Rectangle:
width = W-2
length = (W+4) - 2
New Area = (W-2)x{(W+4)-2}

You are told that the original area is reduced by 24 cm squared. So, the new are is 24 cm squared less than the original area. So we have:

New area = Original area - 24cm, OR

(W-2)x{(W+4)-2} = Wx(W+4) -24
(W-2)x(W+2) = W^2 + 4W - 24
W^2 - 4 = W^2 + 4W -24

Therefore:
4W = 20
W = 5 cm (original width)
L = 5 + 4 = 9 cm (original length)

Answer 2

a rectangle is 4cm longer than its wide.if the length and width are both decreased by 2cm, the area is decreased by 24cmSquared. find the dimensions of the original rectangle?

l = w + 4

area = lw = (w + 4) w = w² + 4w

if the length and width are both decreased by 2cm, the area would be
new area = (l - 2)(w - 2) = (w + 4 - 2)(w - 2)= (w + 2)(w - 2)
=w² - 4

the area is decreased by 24 cm..
area - new are = (w² + 4w) - (w² - 4)= 4w + 4 = 24

w = 5, l = 9
check:
area = 45
new area = 3 * 7 = 21
difference = 24
So width = 5 cm, length = 9 cm

Answer 3

Let l be the length and b the breadth of the rectange. l = b + 4 cm

Area = l x b = b x (b + 4) = b^2 + 4b

Your question is not clear after that. By how much are the length and breadth reduced?

Answer 4

u kannot decrease rectangle in square and if rectangle have 4cm lenght and it is 2cm in width then rectangle will b 16cm.

Answer 5

Something's missing in your question...

If the length and width are both decreased by *what*?

Answer 6

hi...

i think you lost some of the information....