Scince log(base b)a = log a / log b (base 10)
Scince log(base a)b = log b / log a (base 10)
So log(base2) 10 = 1/ [log(base10) 2] = 1/0.301= 3.322259
2007-06-13 02:07:07
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answer #1
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answered by a_ebnlhaitham 6
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Log(base2)10=log(base10)10/log(base10)2=1/0.301
2007-06-13 09:05:11
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answer #2
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answered by Anonymous
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log(base2) 10 = log 10/ log 2 = 1/0.301 = 3.32
2007-06-13 09:29:03
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answer #3
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answered by guest 1
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Since Log(base x) y = 1/ Log(base y) x...
Log (base 2) 10 = 1 / 0.301 = 3.3222
2007-06-13 09:08:10
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answer #4
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answered by blighmaster 3
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log*(base10)2=0.301
log(base2)10=1/0.301=3.32
2007-06-13 09:08:26
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answer #5
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answered by Anonymous
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10^(0.301) = 2
10 = 2^(1/0.301)
10 = 2^(3.32)
log2 (10) = log2 (2^(3.32))
log2(10) = 3.32
2007-06-13 12:02:44
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answer #6
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answered by Como 7
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