4x - 2y = 17
4x - 2y - 4x = - 4x + 17
- 2y = - 4x + 17
- 2y / - 2 = - 4x / - 2 + (17 / - 2)
y = 4/2x + (- 17/2)
y = 2x - 17/2
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Slope is 2
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2007-06-13 02:21:42
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answer #1
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answered by SAMUEL D 7
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Typically, one can write a linear equation in the format of y=mx + b where m is the slope and b is the y-intercept.
So, let's re-arrange the equation and solve for y.
4x - 2y = 17 so add 2y to each side of the equation and you get:
4x = 2y + 17 Now subtract 17 from each side of the equation and you get:
4x - 17 = 2y Now divide both sides of the eqation by 2 and you get:
y = 2x - 17/2
So, the slope is 2 (based on the y = mx + b format)
2007-06-13 01:54:33
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answer #2
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answered by RG 3
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What is the slope for 4x - 2y = 17
Convert the equation in the form
y = mx + b
where m = slope
b = y-intercept
_______________
4x - 2y = 17
-2y = -4x + 17
-2y/-2 = -4x/-2 + 17/-2
y = 2x - 17/2
Therefore, the slope is 2
2007-06-13 01:52:49
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answer #3
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answered by detektibgapo 5
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4x - 2y = 17
Re-arrange so that y remains positive,
2y = 4x - 17
y = (4x - 17)/2
= 2x - 17/2
Equation for line: y = mx + c
where m is the slope,
so in this case, the slope, m = 2
2007-06-13 01:54:10
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answer #4
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answered by jurassicko 4
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the slope is 2 because u simplify by getting y be itself.
so 4x=17-2y
then 4x-17=2y
finally 2x -(17/2)=y so the slope is 2
2007-06-13 01:54:51
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answer #5
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answered by Anonymous
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y = mx +b where m is the slope and b is the y intercept
4x - 2y = 17
-2y = -4x +17
y = 2x -17/2
slope is 2
2007-06-13 01:49:53
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answer #6
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answered by Croasis 3
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normal linear equation :
y = ax + b
a = slope b = y-intercept
4x - 2y = 17
2y = -4x -17
y = -2x - 17/2
slope = -2
since its negative, ur line is downward sloping
2007-06-13 04:49:38
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answer #7
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answered by marionette_presto 3
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4x-2y=17
-2y=17-4x
-y = 17/2 - 2x
y = 2x - 17/2
So, the slope is 2.
2007-06-13 01:51:06
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answer #8
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answered by Peter B. 2
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4x-2y=17
or 4x-17=2y
or 2x-8.5=y
so slope =2
2007-06-13 23:39:12
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answer #9
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answered by Sumita T 3
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4x-2y=17
2y = 4x -17
y = 2x -8.5
Slope = 2
2007-06-13 01:52:20
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answer #10
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answered by Anonymous
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