Electronics?

Question

A power source can supply 12V and 500mA, but the load requires can hold up to 5 watt of power why does not the load blast up. If the theory is that load is sucking the power it only requires to operate than why does in real life our appliances gets busted when voltage or current becomes a bit high.

Answer 1

To continue tlbs101's answer, if your load consumes 500mA at 12V, then it is a 24 Ohm load. So if I increase the voltage to say 15V, I get 625mA, which is 9.375W. This is why things "get busted" when voltage spikes occur

Answer 2

"A power source can supply 12V and 500mA, but the load requires can hold up to 5 watt of power why does not the load blast up?"

Just because a power supply can supply 6 Watts (12V * 0.5A)of power doesn't mean it will force 6 Watts into a load that it rated for 5 Watts. The load will only draw the necessary power (5 Watts) from the source. So long as the load requires 12 Volts it will only draw 417 mA (5 Watts).

That means that the power supply is, perhaps, underutilized, but for other reasons it is generally good to have "headroom" in your power supply.

.

Answer 3

Here your power supply is of 12*500m = 6w
Means that power supply can supply maximum 6w of power but it can supply less than 6w
When you connect a load of 5W to this source current drawn from this source is 5/12=0.4 amp.
Even if you connect a load of 1w then also your load will not burnt(busted)

Answer 4

Load are specified as to input voltage or current ; loads can be considered like a resistor. A 1ohm, 1w resistor is fine as long as you don't supply it more than 1V. Supply more than that, and its current and power dissipation will go to dangerous levels and it will burn itself out.

Answer 5

Blast up or not is depanding on the load resistence