i checked everywhere
2007-06-08 06:02:12 · 8 answers · asked by chris 1 in Science & Mathematics ➔ Engineering
1.5V
2007-06-08 06:05:50 · answer #1 · answered by Anonymous · 0⤊ 4⤋
Yes, I too, saw that e-mail floating around. It has to be a lantern battery from the present times, cause just this past weekend we opened a older lantern battery, ie metal outside casing and it didn't have 32 AA batteries, it had 4 very large ie. D-cell batteries in it. But I'm wanting to go buy a plastic cased lantern battery and see for myself! Now where did I put those wire cutters and screw driver? I only hope the manufactures don't get wind of this, or we are all sunk. That darn lantern battery will cost $100.00 dollars. lol
2016-04-01 10:12:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If you really mean amps, even quite small batteries will deliver suprisingly large currents when they are fresh. Briefly short a new battery through a current meter. You will probably see a current of 5A or more.
If, as I suspect, you really mean ampere-hours, a small battery like an AA will have a low rating, maybe about 1 or 2Ah, depending on whether it is an alkaline or old-fashioned zinc-carbon type. Some newer alkalines will give about 2.5Ah.
2007-06-08 07:02:51 · answer #3 · answered by rrabbit 4 · 0⤊ 0⤋
NiCad and NiMH AA batteries are generally rated for about 2 Amp-hours. Alkaline AA batteries will run slightly higher -- 2.5 Amp-hours.
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2007-06-08 06:15:01 · answer #4 · answered by tlbs101 7 · 0⤊ 0⤋
Oh yes, maybe I can answer this one.
AA batteries have internal resistance r. The maximum amperage will be the minimum resistance, so we simply short-circuit (+) and (-) using cables. That's the maximum ampere.
I've conducted a test and I have one AA Alkaline battery has 0.196 ohm internal resistance, theoritically the
max ampere = 1.5V / 0.196 ohm
= 7.65 A
unfortunately when you put Amperemeter between (+) and (-) you can read the ampere
Amperemeter = 1.5V / ( 0.196 + 0.1 ) ohm
= 5.06 A
because amperemeter do have internal resistance also ( I assumed 0.1 ohm ).
2007-06-08 18:32:34 · answer #5 · answered by amrobyono 3 · 1⤊ 0⤋
about 5 amps
2007-06-09 21:29:13 · answer #6 · answered by Dr. Eddie 6 · 0⤊ 0⤋
Amps is current. and it depends on the resistance of your circuit through Ohms law.
V=IR.
Since it have 1.5 Volts, the R (resistance) of your circuit will determine your current (also know as amperage).
2007-06-08 06:08:41 · answer #7 · answered by Phillip 3 · 0⤊ 0⤋
Voltage = I (current) * R (resistance)
V/R = I (current)
*I is current and the SI unit for current is amperes. The SI unit for voltage is volts and the SI unit for resistance is Ohms (omega).
2007-06-08 06:11:50 · answer #8 · answered by AO7 2 · 0⤊ 0⤋