let "anti-xtian question = a"
if "a", then delete for "Violation of Community Guidelines"
2007-06-06 11:07:46
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answer #1
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answered by Anonymous
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Let X = the amount of angry, repressive individuals of a certain faith
Let Y = the amount of time X spends online
Let Z = the depth of the religious question
Let C = the number of X answers to Z
Let N = how many people with impartiality to the question's 'offensiveness' have answered prior to C
If X time Y divided by C is greater than N, then the question will be deleted at very rapid rate.
If X time Y divided by C is equal to N, then the universe shall crush itself, for there can never be equailty in this equation!
If this is X time Y divided by C is less than N, the question will survive until it can be resolved.
2007-06-06 18:20:14
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answer #2
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answered by Anonymous
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0 / 0 = 1
2007-06-06 18:10:50
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answer #3
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answered by Lost. at. Sea. 7
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You could use Spearman's rank correlation coefficient to test whether there is any relationship between specific religious questions and deletion. it is used to discover the strength of a link between two sets of data (ie. the number of religious questions of a specific kind, and the number of corresponding deletions).
~PhoeniX~
2007-06-06 18:17:17
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answer #4
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answered by Spurious 3
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I think bigotry and religious fundamentalism together with insulting and inane posts is what makes the internet so great and fun. Say no to any kind of censorship!!
2007-06-06 18:09:01
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answer #5
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answered by Anonymous
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The opposite of Z->Z^2+C. The direct opposite.
I suppose that would be G->O^D+Yahoo=newaccount
2007-06-06 18:11:50
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answer #6
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answered by Anonymous
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humorless + stupidy= deletion trend ^ 5
2007-06-06 18:09:16
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answer #7
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answered by Jorge 4
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Oh squirrel, you are making my brain hurt. Be careful, yesterday someone said using the word nihilism was trolling, as she did not know what it meant. Equation is even harder to understand.
2007-06-06 18:08:11
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answer #8
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answered by in a handbasket 6
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3=r +1q - 1d +1t
2007-06-06 18:08:48
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answer #9
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answered by Dean D 2
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f(x) = e^x; where x = number of Yahoo employees with nothing better to do than stalk particular answerers.
2007-06-06 18:07:50
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answer #10
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answered by Anonymous
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