how do i get rid of the logs in the question: ln a - ln 7 = 5 ln b ?

Answer 1

ln a - ln b = ln (a/b) and a*ln b = (ln b^a)
therefore ln a - ln 7 = 5 ln b
ln(a/7) = ln (b^5)
now taking antilog on bothsides
a/7=b^5

Answer 2

ln a- ln 7 = 5 ln b

ln a - ln 7 = ln a/7 => ln a/7= 5 ln b ( now u can reduce ln and u will ne left with ) : a/7= 5b

Answer 3

express each side a a log of a singe expression (preferablly the same base). then take the anti-log (or raise the base to each side of the eaquation)

ln a - ln 7 = 5 ln b

would then be

ln (a/7) = ln (b^5)

then take the anti-log (or raise the base to each side of the equation). in this case raise e to ln (a/7) and ln (b^5). we get

a/7 = b^5

Answer 4

ln (a/7) = ln b^5
a / 7 = b^5
a = 7.b^5

Answer 5

take antilog
a/7=b^5

Answer 6

lna - ln7 = 5 lnb
ln(a/7) = lnb^5
a/7 = b^5