how do u do this problem! plzz help it's for my final tomorrow....?

Question

x^2 - 6x + 9 =0

Answer 1

This is a quadratic equation which u can solve using the foil method or using the quadratic formula. Since the problem looks simple, we can directly use the foil method.

x^2 - 6x + 9

by factoring

(x -3) * (x - 3)

Equating each factor to zero yields:
x-3 = 0
x = 3

hope this helps :)

Answer 2

X^2 - 6x +9 = 0

Ok first, you have to factor this problem. Start with the last term; 9.

The factors for 9 are 1,9 and 3,3 right?

So which of these pairs, when combined makes the second term (6x)? 3,3!

So now, all you have to do is set it up and figure out if they're positive or negative. Because 6 is negative (-6x) and 9 is positive, (+9) you can conclude that they are both negative.

Here's how. Set up your factored equation:

(x ? 3) (x ? 3)

+3 and +3 will give you the +9, but also yields a +6.
-3 and +3 gets you no 6 and a -9.
but -3 and -3 give you your -6x and your +9.

So the factored form is:

(x - 3)(x - 3)=0

Now, because any number multiplied by 0 = 0, you can assume this:

x - 3=0 ; so x = 3.

Hope this helps! Good luck!

Answer 3

two numbers, multiplied together to get positive 9 but add to get -6... (-3)

x^2 has only multiple of 1 components so leave it at X.
(x-3)(x-3)

Answer 4

remember your rules?
(a+b) ^2 = a^2 + 2ab +b^2
(a-b)^2 = a^2 -2ab + b^2
so for this question
a is x and b is 3
cuz it's
(x-3)^2 = x^2 - 2 times 3 times x + (3)^2
so x= 3

or you can also use
use cross multiplication my dear
x - 3 I- 3x
x - 3 I -3x
--------I-------
x^2 9 I -6x


so the answer is (x-3)(x-3)=0
x=3 still :D

Answer 5

No eye dear