5 4 7 0 3 6 3 4 0 8?
the average number of errors
a2
b2.5
c3
d3.5
e4
2007-06-05 19:49:05 · 8 answers · asked by suryya j 1 in Science & Mathematics ➔ Mathematics
e. 4
5+4+7+0+3+6+3+4+0+8=40
40/10 = 4
Hope this helps!
2007-06-05 19:51:16 · answer #1 · answered by p37ry 5 · 0⤊ 0⤋
4
2007-06-06 03:26:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4+5+7+0+3+6+3+4+0+8 = 40
Then divide by no. of pages recorded
= 40/10
=4
2007-06-06 02:52:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Average number of errors per page
= Total no. of errors/No. of pages
=(5 +4 +7 +0+ 3+ 6+ 3 +4+ 0+ 8)/10
=40/10
=4
Ans. e
2007-06-06 02:59:14 · answer #4 · answered by Jain 4 · 0⤊ 0⤋
Add 'em up and divide by 10. That's how you find the average: take the sum and divide by the number of elements. In this case, it is 40 / 10 = 4, e.
2007-06-06 02:51:23 · answer #5 · answered by Horatio 3 · 0⤊ 0⤋
The answer is e 4
2007-06-06 02:53:41 · answer #6 · answered by sweet n simple 5 · 0⤊ 0⤋
e4
2007-06-06 02:53:45 · answer #7 · answered by alb_spec 2 · 0⤊ 0⤋
Are you telling us? or asking us? If your asking...I dont get it. :)
2007-06-06 02:51:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋