the answer is -2over 5
but i need the formala how can we do it
2007-06-05 19:26:32 · 7 answers · asked by suryya j 1 in Science & Mathematics ➔ Mathematics
5y=7-2x
y= 7/5 -2/5x
so gradient= -2/5
2007-06-05 19:31:33 · answer #1 · answered by sweet n simple 5 · 0⤊ 0⤋
the eqn of a straight line is y=mx+c where m is the gradient of the line. so rearrange ur eqn-----
2x+5y=7
y= (-2/5)x +7/5
which makes the gradient -2/5 (m).
2007-06-06 02:33:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Solve for y to put it in slope-intercept form.
5y = -2x + 7
y = -2/5 x + 7/5
The number in front of x (-2/5) is the gradient (or slope).
2007-06-06 02:31:43 · answer #3 · answered by Jim Burnell 6 · 1⤊ 0⤋
well bring 2x to the other side, you get:
5y= -2x + 7 .... then divide by 5
y= -2x/5 + 7/5
so gradient is -2/5
2007-06-06 02:33:53 · answer #4 · answered by alb_spec 2 · 0⤊ 0⤋
2x+5y=7
5y=-2x+7
y=(-2/5)x+(7/5)
y=mx+c
Gradient m =-2/5
2007-06-06 02:40:34 · answer #5 · answered by Jain 4 · 0⤊ 0⤋
write eqn in form of y=mx+c from there m=-2/5 else slope of
ax+by+c=0 is-a/b
2007-06-06 02:31:57 · answer #6 · answered by nipun batra 1 · 0⤊ 0⤋
5y = - 2x + 7
y = (- 2/5).x + 7 / 5
m = - 2 / 5
2007-06-06 05:38:12 · answer #7 · answered by Como 7 · 0⤊ 1⤋