I am trying to solve for "w" and am stuck. any tips? this is the problem: 1800=w^2 +21.55w?

Question

who here is good at math?

Answer 1

w^2 +21.55w-1800=0

w= -b +- sq root of (b^2-4ac) /2a

in this case
a=1
b=21.55
c= -1800

so we get
x= -21.55 +- sq root of [21.55^2 - 4(1)(-1800)] /2(1)

=-21.55 +-87.55 /2

=-21.55 +87.55 /2 or -21.55 -87.55 /2

so x=33 or -54.55

Answer 2

First start by setting the polynomial expression to 0.

1800 = w^2 + 21.55w

w^2 + 21.55w - 1800 = 0

Obviously this cannot be easily factored. So we must use the quadratic formula.

w = [-b ± √(b^2 - 4ac)] / 2a

w = [-21.55 ± √((21.55)^2 - 4(1)(-1800))] / 2(1)

w = -21.55 ± √(464.4025 + 7200) / 2

w = -21.55 ± √(7664.4025) / 2

w = [-21.55 ± 87.5466] / 2

So we have 2 cases to solve for:

w = [-21.55 + 87.5466] / 2
w = 65.9966 / 2
w = 32.9983

AND

w = [-21.55 - 87.5466] / 2
w = -109.0966 / 2
w = -54.5483

So w = {-54.5483, 32.9983} - those are only approximates as the decimals are non-terminating. Hope that helps =)

Answer 3

You can use the quadratic formula: a=1, b= 21.55 and c= -1800. One Appx answer is 33.

Answer 4

its late, and i'm tired + also sick but....

what you need to do is factor that sucker. if you graph it it would look like a parabola, you need to find where it would intersect the x-axis.

if you need to do it the algebra way, does this look familiar:

x^2+21.55x-1800=0

Since there are a lot of decimals, I'd just use the quadratic formula, and wouldnt bother factoring


Hope that helped.

Answer 5

1800=w^2 +21.55w
0 = w^2 + 21.55w - 1800
quadratic formula.

x = (-21.55 +/- sqrt(21.55^2 - 4(-1800)))/2

solve for x and you will get...

32.998 and -54.548