how do you solve this equation?

Question

x^2+12x-13=0

Answer 1

use a*b=0 then a=0 or b=0

x^2+12x-13=0
(x-1)(x+13)=0
then
x =1 or x =-13

Answer 2

step one: x^2+12x-13=0 write the equation
step two: ( - )( + )=0 figure out the signs you use to factor [options are:( - )( - ),( - )( + ), or( + )( - )]
step three: ( x - )( x+ ) put in the number of xs that are being used
step four: ( x - 1)( x + 13) put two numbers that add up to 12 but that multiplys to equal 13
step five: ( x - 1)=0( x + 13)=0 make each equation equal to zero
step six: x=1 and x=13 answer each equation
step seven(optional): ( x - 1)( x + 13)check your answer by distributing
step eight(optional): x^2 + 12x - 13 if it ends up like your original equation you did it right

Answer 3

This quadratic is easily factored; we want two numbers whose product is 13 and whose difference is 12. Since 13 is prime, the only possible factors are 1 and 13, and these work to give (x-1)(x+13) = 0. So the roots are 1 and -13.

Answer 4

x^2+12x-13=0 factor
(x+13)(x-1)=0
x+13=0
x=-13
x-1=0
x=1
solutions are x=-13, 1

Answer 5

(x + 13).(x - 1) = 0
x = - 13 , x = 1

Answer 6

(x+13)(x-1)=0
x+13=0
x=-13
or
x-1=0
x=1

Answer 7

factor it.