(1-2x) - 3(4+5x) +6(7-8x) = 0?

Question

Solve the following equation for the unknown, x.

Answer 1

1-2x-12-15x+42-48x=0
31-65x=0
-65x=-31
x=31/65

Answer 2

(1 - 2x) - 3(4 + 5x) + 6(7 - 8x) = 0
1 - 2x - 12 - 15x + 42 - 48x = 0
(1 - 12 + 42) + (-2x - 15x - 48x) = 0
31 - 65x = 0
31 = 65x
x = 31/65

Answer 3

this is January. If, by using the time you study our solutions, you have no longer resolved those by using your self, i think which you will locate the remainder of the twelve months very, very long. once you have a situation of the style: kx = y (the place x is the variable, and the different letters symbolize numbers), then you definately divide the two aspects by using ok. (ok/ok)x = y/ok bacause ok/ok = a million, you could drop it as a factor: x = y/ok occasion: 3x = 9 (3/3)x = (9/3) x = (9/3) = 3 ----- in case you have a situation of the style: kx + z = y, you start up by using subtracting z from the two aspects: kx + z - z = y - z z - z is 0, so this is dropped in a sum kx = (y-z) that's the same probelm as above, the place x = (y-z)/ok occasion: 6x -15 = 9 6x = 9+15 = 24 x = (9+15)/6 = 24/6 = 4 ------- If the situation is of this style: kx + z = mx + y, then you definately pass by using steps: subtract mx from the two aspects: kx - mx + z = y subract z from the two aspects kx - mx = y-z factor x on the left: (ok-m)x = (y-z) same situation as above: x = (y-z)/(ok-m) occasion: 5x + 3 = 7x - 9 5x - 7x + 3 = -9 5x - 7x = -9 - 3 (5-7)x = -12 x = -12/(5-7) = -12/(-2) = +6 the final thought is to get each and all of the words that comprise the variable on one area, and each thing else on the different. Then divide by using the factor of the variable.

Answer 4

1 - 2x - 12 - 15x + 42 - 48x = 0
31 = 65 x
x = 31 / 65

Answer 5

(1-2x) + (-12-15x) + (42-48x) = 0
(1-12+42) + (-2x-15x-48x) = 0
31-65x = 0
31 = 65x
31/65 = x
.4769230769231=x