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Determine the equation of the line and write in standard form with integer coefficients.

The line through(-2,0) with a solpe of -3/4

2007-06-05 15:17:57 · 7 answers · asked by christopher l 1 in Science & Mathematics Mathematics

7 answers

(y-0) = -3/4 (x+2)
Multiply through by 4 to get
4y = -3x -6
or 3x + 4y = -6.

2007-06-05 15:21:44 · answer #1 · answered by Scarlet Manuka 7 · 0 0

Sure.. the equation of a line is y = mx + b where m is the slope. since you have a slope, plug that in for m. So y = -3/4x +6. Next you solve for b. since you have that plot you can plug in 0 for y and -2 for x and solve. So 0 = -3/4*-2+ c
0 = 3/2 + c
-3/2 = c so the equation is y = -3/4x - 3/2

2007-06-05 22:22:58 · answer #2 · answered by fencingfanatic13 2 · 0 0

y = mx + b
0 = (-3/4)(-2) + b
0 = (3/2) + b
-3/2 = b

so...
y = (-3/4)x - 3/2
multiply through by 4
4y = -3x -6
3x + 4y = -6

2007-06-05 22:29:39 · answer #3 · answered by Marcella S 5 · 0 0

Your slope (m) = -3/4

y = mx + c
sub y=0 abd x=-2

0 = -3/4 * -2 + c
0 = 1.5 + c
c = -1.5

Substituting values into eqn of line (y = mx + c)

y = -3/4x - 1.5
y = -3/4(x+2) . . . . . (ANS)

2007-06-05 22:49:17 · answer #4 · answered by isz_rossi 3 · 0 0

y = mx+b

0=-3/4(-2) + b

b= -6/4

y=-3/4x-6/4

4y=-3x-6

2007-06-05 22:29:02 · answer #5 · answered by Chuck 2 · 0 0

y=mx+b
0=(-3/4)(-2)+b
b=-3/2
4*(y+(3/4)x)=-(3/2)*4
4y+3x=-6

2007-06-05 22:22:23 · answer #6 · answered by Mags 2 · 0 0

y=mx+b
y=(-3/4)x+b
0=(-3/4)(-2)+b
0=(1.5)+b
b=-1.5
y=(-3/4)x-1.5

2007-06-05 22:24:03 · answer #7 · answered by andrea c 4 · 0 0

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