You are a crane operator using a crane with a 210 ft boom. You lift a load so that the load is directly in front of you. You estimate that the angle between the boom and the line between you and the load is 35 degree. About how far are you from the load?
2007-06-05 14:40:14 · 4 answers · asked by mdsmith47 1 in Science & Mathematics ➔ Mathematics
Make sketch of triangle ADL such
angle ADL is 35° , hypotenuse is AD,vertical is AL, horizontal is DL.
AD = 210
cos 35° = DL / 210
DL = 210.cos 35°
DL = 172
Distance from load = 172 ft
2007-06-06 07:35:19 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Draw a picture!!! Make a triange, the hypotenuse is the 210 foot boom, the horizontal leg is the distance from the load to you (this is what you're looking for), and the vertical leg connects between the other two. What you have here is a right angle with a known angle and the known length of the hypotenuse. You're looking for the length of the horizontal leg of the triangle. If you use cosine, you can figure it out. since cosine of an angle=length of the adjacent leg/length of the hypotenuse. You know that the angle is 35 degrees and the length of the hypotenuse is 210 feet. Set it up like this: Cosine of 35 = adjacent leg/ 210 feet and solve it!
2007-06-05 21:49:05 · answer #2 · answered by Jesse H 2 · 0⤊ 0⤋
The boom (crane), cable, and distance from yourself to the load form a right triangle. Draw a diagram. If "x" is the distance between you and the load, then cos(35) = x/210. So x = 210cos(35).
2007-06-05 21:45:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
algebra 1 huh... are u sure it's not trig?
the trig answer should be cos 35deg = x/210, so then x = 210cos35deg = 172ft
2007-06-05 21:47:43 · answer #4 · answered by driftaddict87 4 · 0⤊ 0⤋