plzzzzzzzzzzz help
2007-06-05 14:27:38 · 9 answers · asked by mecca laran 4 in Science & Mathematics ➔ Mathematics
y = -3/2x + anything
2007-06-05 14:29:50 · answer #1 · answered by roar its the Quesadilla rex!! 2 · 1⤊ 0⤋
To find the perpendicular line from your equation, all you do is reciprocate the slope. In your case, the slope, m = 2/3. And the reciprocal of that is 3/2.
Therefore, the perpendicular line is: y = (2x/3) + D. (d can be any number, even 5)
Oh, by the way.. the way you wrote your equation... it is ambiguous. One can interpret it as y = (2/(3x)) + 5. I just assumed it was y = ((2/3)x) + 5. So be careful when you type formulas. lol
2007-06-05 21:38:04 · answer #2 · answered by Tas Chowdhury 2 · 0⤊ 0⤋
y=-3/2x +
Since you didn't specify the intersect point, all you need to worry about is a slope. The original line has the slope of 2/3x. A perpendicular line will have the slope that is negative reciprocal. (that is minus 3/2x)
2007-06-05 21:30:43 · answer #3 · answered by tkquestion 7 · 0⤊ 0⤋
There are infinitely many lines that are perpendicular to y=2/3x + 5.
m1 x m2 = -1 if two lines are perpendicular.
m1 x (2/3) = -1
m1 = -3/2
One such equation is y = (-3/2)x + 9
2007-06-05 21:33:12 · answer #4 · answered by Kemmy 6 · 0⤊ 0⤋
y=2/3x+6
its slope=2/3
slope of perpedicular line=-3/2
its equation is of the form:
y=-3/2 x+constant.
2007-06-05 21:46:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
y= -2/3x+5
2007-06-05 21:32:03 · answer #6 · answered by 'Blank' 3 · 0⤊ 0⤋
There are many line per. to your line. Your line has slope 2/3, per to it = -3/2
So any line y = -3/2 x + any number
2007-06-05 21:30:09 · answer #7 · answered by richardwptljc 6 · 0⤊ 0⤋
gradient of perpendicular line = - 3 / 2
Let this line pass thro` (0,C)
Equation is then:-
y - C = (-3/2).(x - 0)
y = (-3/2).x + C
2007-06-06 04:49:59 · answer #8 · answered by Como 7 · 0⤊ 0⤋
slope should be the negitave reciprocal, no? y = -3/2 + 5
i should know this.
2007-06-05 21:31:24 · answer #9 · answered by Duanerschnitzel 2 · 0⤊ 0⤋