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plz help algebra1

2007-06-05 14:16:52 · 9 answers · asked by mecca laran 4 in Science & Mathematics Mathematics

9 answers

Since you want to find the y-intercept put 0 for x and solve the equation:
5x+y=5
5(0)+y=5
y=5

So the y-intercept is 5

2007-06-05 14:23:50 · answer #1 · answered by someone 2 · 1 0

5

2007-06-05 21:27:19 · answer #2 · answered by UNIQUE 3 · 0 0

Always remember, the point where the line crosses the y axis (the y intercept) is when x = 0. So, in the equation 5x+y = 5
y = 5

2007-06-05 21:30:24 · answer #3 · answered by Bambolero 4 · 0 0

To find the y-intercept, you can either put the equation into slope-intercept form (y = mx + b), where b is the y-intercept, or you can let x = 0 and solve for y.

In slope-intercept form...

5x + y = 5
y = -5x + 5

So b = 5.

Or letting x = 0...

5(0) + y = 5
0 + y = 5
y = 5

So you can also see here it is equal to 5.

For the x-intercept, you let y = 0 and solve for x.

2007-06-05 21:26:02 · answer #4 · answered by JoeSchmo5819 4 · 0 0

Put the equation in slope-intercept form: y = mx + b

y = -5x + 5

The y intercept is 5, the slope is -5

2007-06-05 21:21:28 · answer #5 · answered by dogsafire 7 · 0 0

putx=0,we get,y=5 this is the y-intercept.

2007-06-05 21:31:14 · answer #6 · answered by Anonymous · 0 0

plug 0 for y...
5x=5 so x =1

2007-06-05 21:20:29 · answer #7 · answered by Anonymous · 0 1

5x+y=5
Subtract 5x on both sides and you get y=-5x+5
y=ax+b

b=y intercept
y intercept=5

2007-06-05 21:20:38 · answer #8 · answered by Mike333 2 · 0 0

It's just 5...

(plaese give me the ten points)

2007-06-05 21:27:44 · answer #9 · answered by Gearld GTX 4 · 0 1

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