Math gurus I need your help please with a distance formula question I have tried it over and over again and I?

Question

keep getting this question wrong:(
Please someone help me........................Thank you very much in advance!

(-1,5) and (3,7)

d= (x-x)^2nd (y-y) ^2........................these are supposed to have a little one and a little two and another sign that goes around it.

I keep getting this wrong will someon please help

The answer comes to 2 square root 7
then 17 how

awsome thank you

Answer 1

You seem to be leaving out the square root.

d = sqrt((x2-x1)^2 + (y2-y1)^2)

d = sqrt ((3 - (-1))^2 + (7 - 5)^2)
d = sqrt(4^2 + 2^2)
d = sqrt(16 + 4)
d = sqrt(20)
d = 4.47

Answer 2

The distance formula is the square root of (x2-x1)^2+(y2-y1)^2. So you have (-1,5) and (3,7). Let -1 be x1, 5 be y1, 3 be x2, and 7 be y2. Then plug in the values:

(3-(-1))^2+(7-5)^2

You have(4)^2+(2)^2

16+4=20.

Now take the square root and you will get 2squareroot of 5.

Hope this helps.

Answer 3

The distance formula is
d = √[ (x1 - x2)^2 + (y1 - y2)^2 ]. Did you forget the square root? Maybe even the plus too? Anyway, this gives us:

d = √[ (-1 - 3)^2 + (5 - 7)^2 ]
d = √[ (-4)^2 + (-2)^2 ]
d = √[ 16 + 4 ]
d = √20
d = 2√5

Answer 4

If you have two points in a plane P1 and P2, with (x,y) coordinates (x1, y1) and (x2, y2), then the distance between the ppoints is the length of the line connecting them, which is obtained using the Pythagorean theorem for the length, d, of the hypotenuse of a triangle. Make a picture for yourself so you can follow... d = sqrt( (x1-x2)**2 + (y1 - y2)**2 ). Just plug in the numbers for x1, y1, x2, and y2 as given above from your example into the formula and you have your answer (it is an irrational number between 4 and 5).

Answer 5

Distance = sqrt[(3-(-1))^2 + (7-5)^2] = sqrt[16+4] = sqrt20 = 4.47

Answer 6

Well why don't you tell us what and where and why you mean by "a little one and a little two and another sign that goes around it"? Do you mean exponents? If so where? You can't just say another sign. How is anyone supposed to figure that out when you don't supply us with any information.

I would suggest plugging in numbers for the variables then solving the problem.

Answer 7

d=[ (x1-x2)^2 + (y1-y2)^2 ]^(1/2) ......... (square root of what you had)

d=[ (-1-3)^2 + (5-7)^2 ]^(1/2)
d=[ (-4)^2 + (-2)^2 ]^(1/2)
d=[ 16+ 4 ]^(1/2)
d=[20]^(1/2) ........ (square root of 20)
or d= 2 (5)^(1/2) ...... (2 times the square root of 5)

Answer 8

d^2 = (3 - (-1))^2 + (7-5)^2
d^2 = (4)^2 + (2)^2
d^2 = 16 + 4 = 20
d = 4.47 or 2 x sqrt(5)

Answer 9

distance formula
d(P,R)= sqrt of [(x2-x1)^2 + (y2 - y1)^2]
d(P,R)=sqrt of [(4)^2 + (2)^2]
d=sqrt of [16+4]
d=sqrt of 20 or d(P,R)= 2sqrt5

Answer 10

sq rt [(-1-3)^2 + (5-7)^2]
sq rt (16 + 4) =
sq rt 20 =
2 sq rt 5