physics????

Question

A 0.44 kg rock is projected from the edge of the top of a building with an initial velocity of 9.32 m/s at an angle of 40 degrees above the horizontal . Due to gravity, the rock strikes the ground at a horizontal distance of 15.6 m from the base of the building. Assume the ground is level and that the side of the building is vertical. The acceleration of gravity is 9.8 m/s^2. How tall is the building?


2) A cannon sends a projectile towards a target a distance 1350 m away. The initial velocity makes an angle 33 degrees with the horizontal. The target is hit. The acceleration of gravity is 9.8m/s^2. What is the magnitude of the initial velocity? Answer in units of m/s

Answer 1

Yeah I agree I do that

Answer 2

Integrate d^y/dt^2 = - g. Fit integration constants to conditions. Work it out yourself. That means you.