Again, if the cosine of one angle is the sine of another angle, then the two angles must add up to 90 degrees.
60 + x + 10 = 90, so 70 + x = 90 and x = 20.
2007-06-05 12:21:45
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answer #1
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answered by Anonymous
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The manner you have put brackets in your question answer is
20 degrees
Reason is Cos (20 degrees+ 10 degrees) is cos (30 degrees)!
Then sin60 is also in degrees!
It is well known that sin (60 degrees)= cos (30 degrees)
Therefore value of x = 20 degrees.!
(All this confusion arise from a representing the angles as either degrees or as radians!)
Regards!
2007-06-06 03:58:35
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answer #2
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answered by kkr 3
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Ques: sin 60 = cos (X + 10 degrees) ans => Since, sin and cos are cofunctions.
That is sin (90 - x degrees) = cos x and cos (90 - x degrees) = sin x
Therefore we can rewrite this as cos (90 - 60 degrees) = cos (X + 10 degrees) => cos (30 degrees) = cos (X + 10 degrees) => comparing the degrees, we get 30 = x + 10 which gives x = 20.
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2007-06-05 12:34:27
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answer #3
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answered by Anonymous
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sin60 = cos(90-60) = cos(30)
x + 10 = 30
x = 20
2007-06-05 13:49:02
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answer #4
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answered by UNIQUE 3
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To find the value of x
sin60 = cos(x+10)
Sqrt(3)/2 = cos(x+10)----------------------(1)
We know that Sqrt(3)/2 = cos(30)-----------------(2)
Comparing equation 1 and 2 , we get
x+10 = 30
x = 20
2007-06-05 12:28:30
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answer #5
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answered by Aruldass Classof1 1
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assuming you are using degrees, as opposed to radians -
sin60 = cos(90-60) = cos(30)
x + 10 = 30
x = 20
thank you advance math!
2007-06-05 12:23:44
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answer #6
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answered by Anonymous
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X= 20 deg in the first quadrant and
320 deg in the last quadrant.
2007-06-05 12:24:18
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answer #7
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answered by cattbarf 7
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sin0º = cos90º.
sin10º = cos80º.
sin20º = cos70º.
sin30º = cos60º.
sin40º = cos50º.
sin50º = cos40º.
sin60º = cos30º.
2007-06-05 13:05:14
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answer #8
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answered by Mark 6
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-8.119464091
Plug it in to check.
2007-06-05 12:22:10
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answer #9
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answered by Linduh. 3
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