Anyway, I need a little help in understanding a certain problem.
data 1: 10, 20, 25, 28, 31, 35, 37, 38, 38, 39, 39, 42, 46
data 2: 23, 39, 40, 41, 43, 47, 51, 58, 63, 66, 67, 69, 72
For data 1,
sample mean = 52.23
median = 51
standard deviation = 14.86
upper fourth (or quartile?) = 66
lower fourth (or quartile?) = 41
For data 2,
mean = 32.92
median = 37
SD = 9.93
upper fourth (or quartile?) = 39
lower fourth (or quartile?) = 28
The solutions manual and my TI-83 Plus calculator agrees with me on all those answers except the lower/upper fourths (or quartiles?).
For data 1, my calculator says:
upper quartile = 66.5
lower quartile = 40.5
For data 2, calc says:
upper quartile = 39
lower quartile = 26.5
To find fourths (or quartiles?), I generally understand about splitting your samples in one half of the lower values and the other half of higher values, and then find the median in each of those halves.
2007-06-05
12:08:18
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1 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Mathematics
Also read about including the median in both halves if the number of samples is odd.
Can someone explain or elaborate?
2007-06-05
12:09:02 ·
update #1