In Triangle ABC, if A=5, B=6, and ANGLE C =60, the value of C is?
2007-06-05 11:11:13 · 11 answers · asked by RobertH 1 in Science & Mathematics ➔ Mathematics
cosine rule
c^2 = a^2 + b^2 - 2*a*b*cosC
= 5^2 + 6^2 - 2*5*6*cos60
= 31
c = 5.568
2007-06-05 11:15:50 · answer #1 · answered by Dr D 7 · 1⤊ 1⤋
c=2
2007-06-05 18:20:08 · answer #2 · answered by no name no name 4 · 0⤊ 1⤋
60
2007-06-05 18:19:08 · answer #3 · answered by ButtErFlY 3 · 0⤊ 0⤋
law of cosines
c² = a² + b² - 2acCosC
âc² = ± â(5)² + (6)² - 2(5)(6)Cos60
âc² = ± â25 + 36 - 60(.5)
âc² = ± â61 - 30
âc² = ± â31
c = ± 5.567764363
- - - - - - - -s-
2007-06-05 19:28:52 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
c² = a² + b² - 2ac cos C
c² = 25 + 36 - 2(5)(6) cos 60°
c² = 61 - 60(1/2) = 31
c = â31
2007-06-05 18:16:44 · answer #5 · answered by Philo 7 · 0⤊ 1⤋
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Dr D
c^2 = a^2 + b^2 - 2*a*b*cosC
= 5^2 + 6^2 - 2x5x6xcos60
= 31
c = sqroot ( 31)
2007-06-05 18:35:34 · answer #6 · answered by muhamed a 4 · 0⤊ 1⤋
You would need to use the Law of Cosines (you can read about it here: http://en.wikipedia.org/wiki/Law_of_cosines )
c^2 = a^2 + b^2 - 2ab cos C
c = sqrt(5^2 + 6^2 - 2(5)(6) cos(60))
c = sqrt(25 + 36 - 60 (1/2))
c = sqrt(61 - 30)
c = sqrt(31)
c = 5.567764363
2007-06-05 18:17:52 · answer #7 · answered by Alex 4 · 0⤊ 1⤋
Use the cosine law
a^2+b^-2abcosC = c^2
25+36-2(5*6)cos60 = c^2
c = root 31
2007-06-05 18:17:32 · answer #8 · answered by minorchord2000 6 · 0⤊ 1⤋
Im so good its 5.5677
5^2+6^2-2(5*6)cos(60)
2007-06-05 18:15:25 · answer #9 · answered by chemistryishard 2 · 0⤊ 1⤋
SOH CAH TOA
tan C = 6/5
C = 50 degrees.
2007-06-05 18:18:45 · answer #10 · answered by Anonymous · 0⤊ 1⤋