English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Okay, so..This is a Combined Gas law problem.

I know the equation but i cant get it to work out on here...so if you know how to work out this problem..PLEASE help!!!! Thanks!

2007-06-05 10:58:14 · 2 answers · asked by Mander 1 in Science & Mathematics Chemistry

2 answers

This is Boyle's Law. The temperature obviously doesn't change as there's no final temp'
Volume decreases <===> Pressure increases.
V1 x P1 = V2 x P2
1,000mL x 1 atm = 473mL x P2
P2 = 1,000 ÷ 473
P2 = 2.11atm. Final pressure.

2007-06-05 17:04:16 · answer #1 · answered by Norrie 7 · 0 0

It should be straight forward, using P1V1 = P2V2.

P1 is 1 atm, V1 is 1 L, V2 is 0.473 L, and you are solving for P2. The answer you get will be in atmospheres, and if you need to, you can convert that to kPa or to Torr.

2007-06-05 11:01:19 · answer #2 · answered by hcbiochem 7 · 0 0

fedest.com, questions and answers