Chemistry Acid/Base Titrations?

0 ⤊

Chemistry Acid/Base Titrations?

How many grams of CH3COOH, acetic acid, a monoprotic acid, would be needed to reach an end point with 45.61 mL of 0.175 M KOH?

2007-06-05 10:55:53 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

3 answers

First, calculate the moles of KOH:

0.04561 L X 0.175 mol/L = ____ mol

That will be the correct number of moles of acetic acid needed.

Finally, multiply that number of moles by the molar mass of acetic acid to get grams.

2007-06-05 11:03:36 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋

Convert mL KOH into (L) and multiply to its concentration. The result will be multiplied to the molecular weight of the acetic acid.

2007-06-05 18:03:54 · answer #2 · answered by Alexis 3 · 0⤊ 0⤋

65?

2007-06-05 17:59:15 · answer #3 · answered by Rajagopal N 2 · 0⤊ 0⤋