linear equation again?

Question

two years from now , jorge will be three times old as maria is now. in ten years jorge will be four times old as maria is now.
what are jorge and maria current ages?

Answer 1

This is a systems of equations.

First, define the variables
Let J = Jorge's current age
Let M = Maria's current age

The first equation is: J+2=3M
The second equation is J+10 = 4M

First, subtract the two equations. You get:

-8 = -M or
M=8

Now substitute that into the first equation, and you get:

J + 2 = (3)(8)
J + 2 = 24
J = 22

Substitute these into the second equation to check your work, and you get: 22+10 = (4)(8) or 32=32 so you have your answer.

Answer 2

jorge in 2 years, j+2. maria now, m. jorge in 10 years, j+10. so the equations say

j+2 = 3m
j+10 = 4m

subtract 1st equation from 2nd:

8 = m
j+2 = 3(8)
j = 22

Answer 3

xanyone, you could've just used J and M like everyone else
no need for x and y

j + 2 = 3m
- j +10 = 4m
-----------------
0 + -8 = -1m

or -8 = -m
which means 8=m or m=8

you now have maria
use the equations to find jorge

first equation:
j+2=3m
j+2=3(8)
j+2=24
-2 -2
j=22

second equation:
j+10=4m
j+10=4(8)
j+10=32
-10 -10
j=22

you get it both ways
j=22 and m=8
jorge is 22 now and maria is 8 now

hope this helped

Answer 4

x = jorge
y= maria
x+2 =3y = x-3y =-2
x+10=4y= x-4y=-10
y=8 ,x=22