I have a math assignement due on Fri, and I have no Idea where to start on this question. It's really important to for me to do well in this course. Please help!!
A t.v. antenna casts a shadow that is 75.0 m long. If the angle of the elevation of the sun is 39, calculate how high above the ground a blackbird perched on the top pf the antenna is.
2007-06-05 08:58:33 · 4 answers · asked by AlexMP 2 in Science & Mathematics ➔ Mathematics
Aw. I am sorry to hear you are still in school. You wouldn't happen to be in geometry would you? I did similar questions this year in geom but I only sorta understood trigonometry until it all clicked before exams. It's easy once you understand it. Just make sure you have a calculator that does trig (you can always just use excel if all else fails).
First off, I'd draw a right triangle. The bottom leg is the 75 m shadow and the angle made by that leg and the hypotnuse is the 39 degree angle.
You are trying to find the other leg so you'll need Tangent since you know one leg and you need to know the other.
So your equation would be Tan(39)=x/75. Put Tan(39) over 1 and cross multiply so once put it in terms of x the equation is x=Tan(39)*75
and then you would get your answer. if you need the answer just ask and ill solve it for you later.
2007-06-05 09:10:44 · answer #1 · answered by ANNA 2 · 0⤊ 0⤋
You have a right angle triangle with one leg the shadow and the other leg the tv antenna.The angle between the shadow and the hypotenuse is 39 degrees
so
tan 39 = h/75 so h= 60.73 m
2007-06-05 09:07:22 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
Let h be the height of the antenna.
h/75 = tan(39)
h = 75 tan(39) = 60.73 m
2007-06-05 09:04:09 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
Let h be height of antenna.
tan 39° = h / 75
h = 75.tan 39°
h = 60.7 m
2007-06-05 10:19:40 · answer #4 · answered by Como 7 · 0⤊ 0⤋